# Line slope calculator 4x+7y=50

**Straight line given by points A[2; 6] and B[9; 2]**

## Calculation:

**Slope-intercept form of line:**y = -0.5714x+7.1429

**Canonical form of the line equation:**4x+7y-50 = 0

**Parametric form of the line equation:**

x = 7t+2

y = -4t+6 ; t ∈ R

**Slope:**m = -0.5714

**Slope angle of line: φ =**-29°44'42″ = -0.5191 rad

**X intercept:**x

_{0}= 12.5

**Y intercept:**y

_{0}= q = 7.1429

**Distance line from the origin:**d

_{0}= 6.2017

**The length of the segment AB: |AB| =**8.0623

**Vector: AB =**(7; -4)

**Normal vector: n =**(4; 7)

**Midpoint of the segment AB: M =**[5.5; 4]

**Perpendicular Bisector equation:**7x-4y-22.5 = 0

**Vector OA = (2; 6) ; |OA| = 6.3246**

**Vector OB = (9; 2) ; |OB| = 9.2195**

**Scalar product OA .OB = 30**

**Angle ∠ AOB = 59°2'10″ = 1.0304 rad**